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07/18/2010 04:12 PM by Roger; Where does the # come into it? | [View full text and thread]
06/06/2010 08:55 AM by Pinchas B; Can't Understand... | I am ashamed to admit that I don't understand how did you get the first line u the equation:
W#(p+1) = (x/x+y)(W#(p)+Sy) + (y/x+y)(W#(p)-Sx)
Will you be kind enough to go into details? Many thanks, Pinchas
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06/05/2010 03:13 PM by Emma; Hi | Hi. Can you explain me and simplify the equation and variables and how you solve that? [View full text and thread]
06/04/2010 09:15 PM by skzap; | p is the total number of gladiators S total strength of the field (and therefore constant) T# total strength of team # W# winning chances of team #
for p=2 W#(p) = T#/S
lets admit W#(p) = T#/S for any p, therefore for p+1: team # sends gladiator of strength x and other team of strength y
W#(p+1) = (x/x+y)(W#(p)+Sy) + (y/x+y)(W#(p)-Sx) W#(p+1) = (xW#(p)+yW#(p)) / x+y W#(p+1) = W#(p)
So ... winning chances of a team is proportional to their total number of strength.
Now just a basic ev prooves that order doesn't matter.
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06/01/2010 04:29 PM by Emma; the gladiator game enigma | The game:
There are two gladiators groups. Group A and Group B. Let assume that group A have 20 gladiators and group B have 30 gladiators. Every gladiator have a mark that represent his power in positive integer - 100, 140, 200, 80, [View full text and thread]
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